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攻防世界--crypto--进阶区

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####0x01 你猜猜
我们刚刚拦截了，敌军的文件传输获取一份机密文件，请君速速破解。

密文

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504B03040A0001080000626D0A49F4B5091F1E0000001200000008000000666C61672E7478746C9F170D35D0A45826A03E161FB96870EDDFC7C89A11862F9199B4CD78E7504B01023F000A0001080000626D0A49F4B5091F1E00000012000000080024000000000000002000000000000000666C61672E7478740A0020000000000001001800AF150210CAF2D1015CAEAA05CAF2D1015CAEAA05CAF2D101504B050600000000010001005A000000440000000000

解题思路
504b0304开头，zip格式文件，字符串放在winhex下，重命名为1.zip，解压，发现需要密码，且不是伪加密，使用archpr进行爆破，得到密码为123456，解压，得到flag。en…….>crypto????

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JPEG (jpg)，文件头：FFD8FF
PNG (png)，文件头：89504E47
GIF (gif)，文件头：47494638
TIFF (tif)，文件头：49492A00
Windows Bitmap (bmp)，文件头：424D
CAD (dwg)，文件头：41433130
Adobe Photoshop (psd)，文件头：38425053
Rich Text Format (rtf)，文件头：7B5C727466
XML (xml)，文件头：3C3F786D6C
HTML (html)，文件头：68746D6C3E
Email [thorough only] (eml)，文件头：44656C69766572792D646174653A
Outlook Express (dbx)，文件头：CFAD12FEC5FD746F
Outlook (pst)，文件头：2142444E
MS Word/Excel (xls.or.doc)，文件头：D0CF11E0
MS Access (mdb)，文件头：5374616E64617264204A
WordPerfect (wpd)，文件头：FF575043
Postscript (eps.or.ps)，文件头：252150532D41646F6265
Adobe Acrobat (pdf)，文件头：255044462D312E
Quicken (qdf)，文件头：AC9EBD8F
Windows Password (pwl)，文件头：E3828596
ZIP Archive (zip)，文件头：504B0304
RAR Archive (rar)，文件头：52617221
Wave (wav)，文件头：57415645
AVI (avi)，文件头：41564920
Real Audio (ram)，文件头：2E7261FD
Real Media (rm)，文件头：2E524D46
MPEG (mpg)，文件头：000001BA
MPEG (mpg)，文件头：000001B3
Quicktime (mov)，文件头：6D6F6F76
Windows Media (asf)，文件头：3026B2758E66CF11
MIDI (mid)，文件头：4D546864

flag

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daczcasdqwdcsdzasd

####0x02 enc
Fady不是很理解加密与编码的区别 所以他使用编码而不是加密，给他的朋友传了一些秘密的消息。

密文

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解题思路
ZERO–>0，ONE–>1，去掉空格，得到一串01编码，转化为ascii码，得到一段base64编码，base64解密，得到一段摩斯密码，摩斯解密，得到alexctfth15o1so5up3ro5ecr3totxt，<7A7>???，自己添添改改最终得到flag为

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```
#!/usr/bin/env python3
# -*- coding:utf-8 -*-

import base64

s = '0100110001101001001100000110011101001100011010010011000001110101010011000110100101000001011101010100100101000011001100000111010101001100011010010011000001100111010011000101001100110100011101000100110001101001010000010111010001001001010000110011010001110101010011000101001100110100011001110100110001010011010000010111010101001100011010010011010001110101010010010100001100110100011101000100110001010011001100000111010001001001010000110011010001110101010011000110100100110100011101010100100101000011001100000111010001001100010100110100000101110101010011000101001100110000011101000100110001010011010000010111010101001100011010010011010001100111010011000101001100110000011101000100100101000011001101000111010101001100011010010011010001110101010010010100001100110100011101010100110001010011010000010111010101001100010100110011000001110101010010010100001100110100011101010100110001101001001100000111010001001001010000110011010001110100010011000110100101000001011101000100110001010011001100000110011101001100011010010011010001110101010011000110100100110100011001110100110001101001010000010111010001001100011010010011000001110101010010010100001100110100011101000100110001101001010000010111010101001100011010010011010001110100010011000101001101000001011101000100100101000011001100000111010001001100010100110100000101110100010010010100001100110000011101010100110001101001001100000110011101001100010100010011110100111101'
flag = ''
for i in range(0,len(s),8):
    flag += chr(int(s[i:i+8],2))

flag = base64.b64decode(flag).decode('ascii')

CODE_TABLE = {
    # 26 个英文字符
    'A': '.-', 'B': '-...', 'C': '-.-.',
    'D': '-..', 'E': '.', 'F': '..-.',
    'G': '--.', 'H': '....', 'I': '..',
    'J': '.---', 'K': '-.-', 'L': '.-..',
    'M': '--', 'N': '-.', 'O': '---',
    'P': '.--.', 'Q': '--.-', 'R': '.-.',
    'S': '...', 'T': '-', 'U': '..-',
    'V': '...-', 'W': '.--', 'X': '-..-',
    'Y': '-.--', 'Z': '--..',

    # 10 个数字
    '0': '-----', '1': '.----', '2': '..---',
    '3': '...--', '4': '....-', '5': '.....',
    '6': '-....', '7': '--...', '8': '---..',
    '9': '----.',

    # 16 个特殊字符
    ',': '--..--', '.': '.-.-.-', ':': '---...', ';': '-.-.-.',
    '?': '..--..', '=': '-...-', "'": '.----.', '/': '-..-.',
    '!': '-.-.--', '-': '-....-', '_': '..--.-', '(': '-.--.',
    ')': '-.--.-', '$': '...-..-', '&': '. . . .', '@': '.--.-.'

    # 你还可以自定义

}

def morsedecode(morse):
    msg =''
    codes = morse.split(' ')
    for code in codes:
        if code =='':
            msg += ' '
        else:
            UNCODE =dict(map(lambda t:(t[1],t[0]),CODE_TABLE.items()))
            msg += UNCODE[code]
    return msg

FLAG = morsedecode(flag)
flag = FLAG.lower()
print('flag is ',flag)

flag

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ALEXCTF{TH15_1S_5UP3R_5ECR3T_TXT}
`

####0x03 告诉你个秘密
密文

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636A56355279427363446C4A49454A7154534230526D6843
56445A31614342354E326C4B4946467A5769426961453067

解题思路
16进制转ASCII得到一段base64编码，base64解密得到键盘密码，解密得到flag为

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脚本

#!/usr/bin/env python3

-- coding:utf-8 --

import base64

s1 = ‘636A56355279427363446C4A49454A7154534230526D6843’
s2 = ‘56445A31614342354E326C4B4946467A5769426961453067’

def f(s):
flag = ‘’
for i in range(0, len(s), 2):
flag += chr(int(s[i:i + 2], 16))
s3 = base64.b64decode(flag).decode(‘ascii’)
print(s3)
f(s1)
f(s2)

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flag

TONGYUAN

####0x04 Easy-one
破解密文，解密msg002.enc文件


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